If matter has wave-like aspects and a de Broglie wavelength, then the expression must somehow apply to matter. How? And what are the implications?
Consider a particle with velocity as it travels along the -axis with de Broglie wavelength . Figure 39.11 showed a history graph of a wave packet that might represent the particle as it passes a point on the -axis. It will be more useful to have a snapshot graph of the wave packet traveling along the -axis.
The time interval is the duration of the wave packet as the particle passes a point in space. During this interval, the packet moves forward
where is the -component of the particle’s momentum. The quantity , shown in FIGURE 39.16, is the length or spatial extent of the wave packet. Conversely, we can write the wave packet’s duration in terms of its length as
You will recall that any wave with sinusoidal oscillations must satisfy the wave condition . For a material particle, where is the de Broglie wavelength, the frequency is
If the momentum should vary by the small amount , the frequency will vary by the small amount . Assuming that and (reasonable assumptions), we can treat and as if they were differentials and . Taking the derivative, we find
Multiplying together these expressions for and , we find that
Because for any wave, one last rearrangement of Equation 39.27 shows that a matter wave must obey the condition
This statement about the relationship between the position and momentum of a particle was proposed by Werner Heisenberg, creator of one of the first successful quantum theories. Physicists often just call it the uncertainty principle.
NOTE In statements of the uncertainty principle, the right side is sometimes , as we have it, but other times it is just or contains various factors of . The specific number is not especially important because it depends on exactly how and are defined. The important idea is that the product of and for a particle cannot be significantly less than Planck’s constant h. A similar relationship for applies along the -axis.