33.4.3 The Width of a Single-Slit Diffraction Pattern

It is easier to measure positions on the screen rather than angles. The position of the pth dark fringe, at angle θp, is yp=L tan θp, where L is the distance from the slit to the viewing screen. Using Equation 33.20 for θp and the small-angle approximation tan θp≈θp, we find that the dark fringes in the single-slit diffraction pattern are located at

yp=pλ Lap=1, 2, 3, …(positions of dark fringes) (33.21)

A diffraction pattern is dominated by the central maximum, which is much brighter than the secondary maxima. The width w of the central maximum, shown in Figure 33.15, is defined as the distance between the two p=1 minima on either side of the central maximum. Because the pattern is symmetrical, the width is simply w=2y1. This is

w=2λ La(single slit) (33.22)

The width of the central maximum is twice the spacing λL/a between the dark fringes on either side. The farther away the screen (larger L), the wider the pattern of light on it becomes. In other words, the light waves are spreading out behind the slit, and they fill a wider and wider region as they travel farther.

A photo of a single slit diffraction pattern with a white band at the center.

The central maximum of this single-slit diffraction pattern appears white because the photo is overexposed. The width of the central maximum is clear.

Full Alternative Text

An important implication of Equation 33.22, one contrary to common sense, is that a narrower slit (smaller a) causes a wider diffraction pattern. The smaller the opening you squeeze a wave through, the more it spreads out on the other side.

EXAMPLE 33.4 Determining the wavelength

Light passes through a 0.12-mm-wide slit and forms a diffraction pattern on a screen 1.00 m behind the slit. The width of the central maximum is 0.85 cm. What is the wavelength of the light?

SOLVE From Equation 33.22, the wavelength is

λ=aw2L=(1.2×10−4 m)(0.0085 m)2(1.00 m)=5.1×10−7 m=510 nm