33.3 The Diffraction Grating

Suppose we were to replace the double slit with an opaque screen that has N closely spaced slits. When illuminated from one side, each of these slits becomes the source of a light wave that diffracts, or spreads out, behind the slit. Such a multi-slit device is called a diffraction grating. The light intensity pattern on a screen behind a diffraction grating is due to the interference of N overlapped waves.

NOTE   The terms “interference” and “diffraction” have historical roots that predate our modern understanding of wave optics, and thus their use can be confusing. Physically, both arise from the superposition of overlapped waves. Interference usually describes a superposition of waves coming from distinct sources—as in double-slit interference. Diffraction usually describes how the superposition of different portions of a single wave front causes light to bend or spread after encountering an obstacle, such as a narrow slit. Diffraction is important in a diffraction grating because light does spread out behind each slit, but the intensity pattern seen behind a diffraction grating results from the interference of light waves coming from each of the slits. It might more logically be called an interference grating, but it’s not. Don’t let the name confuse you.

FIGURE 33.7 shows a diffraction grating in which N slits are equally spaced a distance d apart. This is a top view of the grating, as we look down on the experiment, and the slits extend above and below the page. Only 10 slits are shown here, but a practical grating will have hundreds or even thousands of slits. Suppose a plane wave of wavelength λ approaches from the left. The crest of a plane wave arrives simultaneously at each of the slits, causing the wave emerging from each slit to be in phase with the wave emerging from every other slit. Each of these emerging waves spreads out, just like the light wave in Figure 33.2, and after a short distance they all overlap with each other and interfere.

FIGURE 33.7 Top view of a diffraction grating with N=10 slits.

The figure illustrates the top view of a diffraction grating in which N slits are equally spaced at distance d apart.
FIGURE 33.7 Full Alternative Text

We want to know how the interference pattern will appear on a screen behind the grating. The light wave at the screen is the superposition of N waves, from N slits, as they spread and overlap. As we did with the double slit, we’ll assume that the distance L to the screen is very large in comparison with the slit spacing d; hence the path followed by the light from one slit to a point on the screen is very nearly parallel to the path followed by the light from neighboring slits. The paths cannot be perfectly parallel, of course, or they would never meet to interfere, but the slight deviation from perfect parallelism is too small to notice. You can see in Figure 33.7 that the wave from one slit travels distance Δr=d sin θ more than the wave from the slit above it and Δr=d sin θ less than the wave below it. This is the same reasoning we used in Figure 33.5 to analyze the double-slit experiment.

Figure 33.7 is a magnified view of the slits. FIGURE 33.8 steps back to where we can see the viewing screen. If the angle θ is such that Δr=d sin θ=mλ, where m is an integer, then the light wave arriving at the screen from one slit will be exactly in phase with the light waves arriving from the two slits next to it. But each of those waves is in phase with waves from the slits next to them, and so on until we reach the end of the grating. In other words, N light waves, from N different slits, will all be in phase with each other and interfere constructively when they arrive at a point on the screen at angle θm such that

d sin θm=mλm=0, 1, 2, 3, … (33.15)

The screen will have bright constructive-interference fringes at the values of θm given by Equation 33.15. We say that the light is “diffracted at angle θm."

FIGURE 33.8 Angles of constructive interference.

The figure illustrates plane wave diffracting through a diffraction grating.
FIGURE 33.8 Full Alternative Text

Because it’s usually easier to measure distances rather than angles, the position ym of the mth maximum is

ym=L tan θm(positions of bright fringes) (33.16)

The integer m is called the order of the diffraction. For example, light diffracted at θ2 would be the second-order diffraction. Practical gratings, with very small values for d, display only a few orders. Because d is usually very small, it is customary to characterize a grating by the number of lines per millimeter. Here “line” is synonymous with “slit,” so the number of lines per millimeter is simply the inverse of the slit spacing d in millimeters.

The figure illustrates a microscopic side- on view of a diffraction grating.

A microscopic side-on look at a diffraction grating.

Full Alternative Text

NOTE   The condition for constructive interference in a grating of N slits is identical to Equation 33.4 for just two slits. Equation 33.15 is simply the requirement that the path-length difference between adjacent slits, be they two or N, is mλ. But unlike the angles in double-slit interference, the angles of constructive interference from a diffraction grating are generally not small angles. The reason is that the slit spacing d in a diffraction grating is so small that λ/d is not a small number. Thus you cannot use the small-angle approximation to simplify Equations 33.15 and 33.16.

The wave amplitude at the points of constructive interference is Ne because N waves of amplitude e combine in phase. Because the intensity depends on the square of the amplitude, the intensities of the bright fringes of a diffraction grating are

Imax=N2I1 (33.17)

where, as before, I1 is the intensity of the wave from a single slit. You can see that the fringe intensities increase rapidly as the number of slits increases.

Not only do the fringes get brighter as N increases, they also get narrower. This is again a matter of conservation of energy. If the light waves did not interfere, the intensity from N slits would be NI1. Interference increases the intensity of the bright fringes by an extra factor of N, so to conserve energy the width of the bright fringes must be proportional to 1/N. For a realistic diffraction grating, with N>100, the interference pattern consists of a small number of very bright and very narrow fringes while most of the screen remains dark. FIGURE 33.9a shows the interference pattern behind a diffraction grating both graphically and with a simulation of the viewing screen. A comparison with Figure 33.6b shows that the bright fringes of a diffraction grating are much sharper and more distinct than the fringes of a double slit.

FIGURE 33.9 The interference pattern behind a diffraction grating.

The figure labeled (“a”) illustrates an interference pattern when a light passes through a diffraction grating both graphically and with a simulation of the viewing screen.
The figure illustrates that the bright fringes of a diffraction grating are much sharper and more distinct than the fringes of a double slit.
Full Alternative Text

Because the bright fringes are so distinct, diffraction gratings are used for measuring the wavelengths of light. Suppose the incident light consists of two slightly different wavelengths. Each wavelength will be diffracted at a slightly different angle and, if N is sufficiently large, we’ll see two distinct fringes on the screen. FIGURE 33.9b illustrates this idea. By contrast, the bright fringes in a double-slit experiment are too broad to distinguish the fringes of one wavelength from those of the other.

EXAMPLE 33.2 Measuring wavelengths emitted by sodium atoms

Light from a sodium lamp passes through a diffraction grating having 1000 slits per millimeter. The interference pattern is viewed on a screen 1.000 m behind the grating. Two bright yellow fringes are visible 72.88 cm and 73.00 cm from the central maximum. What are the wavelengths of these two fringes?

VISUALIZE This is the situation shown in Figure 33.9b. The two fringes are very close together, so we expect the wavelengths to be only slightly different. No other yellow fringes are mentioned, so we will assume these two fringes are the first-order diffraction (m=1).

SOLVE The distance ym of a bright fringe from the central maximum is related to the diffraction angle by ym=L tan θm. Thus the diffraction angles of these two fringes are

θ1=tan−1(y1L)={36.08°fringe at 72.88 cm36.13°fringe at 73.00 cm

These angles must satisfy the interference condition d sin θ1=λ, so the wavelengths are λ=d sin θ1. What is d? If a 1 mm length of the grating has 1000 slits, then the spacing from one slit to the next must be 1/1000 mm, or d=1.000×10−6 m. Thus the wavelengths creating the two bright fringes are

λ=d sin θ1={589.0 nmfringe at 72.88 cm589.6 nmfringe at 73.00 cm

REVIEW We had data accurate to four significant figures, and all four were necessary to distinguish the two wavelengths.

The science of measuring the wavelengths of atomic and molecular emissions is called spectroscopy. The two sodium wavelengths in this example are called the sodium doublet, a name given to two closely spaced wavelengths emitted by the atoms of one element. This doublet is an identifying characteristic of sodium. Because no other element emits these two wavelengths, the doublet can be used to identify the presence of sodium in a sample of unknown composition, even if sodium is only a very minor constituent. This procedure is called spectral analysis.