29.7.4 The Hall Effect

A charged particle moving through a vacuum is deflected sideways, perpendicular to v ⃗, by a magnetic field. In 1879, a graduate student named Edwin Hall showed that the same is true for the charges moving through a conductor as part of a current. This phenomenon—now called the Hall effect—is used to gain information about the charge carriers in a conductor. It is also the basis of a widely used technique for measuring magnetic field strengths.

FIGURE 29.41a shows a magnetic field perpendicular to a flat, current-carrying conductor. You learned in Chapter 27 that the charge carriers move through a conductor at the drift speed vd. Their motion is perpendicular to B⃗, so each charge carrier experiences a magnetic force FB=evdB perpendicular to both B⃗ and the current I. However, for the first time we have a situation in which it does matter whether the charge carriers are positive or negative.

FIGURE 29.41 In a magnetic field, the charge carriers of a current are deflected to one side.

The figure labeled (“a”) illustrates the deflection of a charge in a magnetic field.
The figure labeled (b) illustrates the deflection of a charge in both magnetic and electric fields.
The figure labeled (c) illustrates the deflection of a charge in both magnetic and electric fields.
Full Alternative Text

FIGURE 29.41b, with the field pointing toward you, shows that positive charge carriers moving in the direction of I are pushed toward the bottom surface of the conductor. This creates an excess positive charge on the bottom surface and leaves an excess negative charge on the top. FIGURE 29.41c, where the electrons in an electron current i move opposite the direction of I, shows that electrons would be pushed toward the bottom surface. (Be sure to use the right-hand rule and the sign of the electron charge to confirm the deflections shown in these figures.) Thus the sign of the excess charge on the bottom surface is the same as the sign of the charge carriers. Experimentally, the bottom surface is negative when the conductor is a metal, and this is one more piece of evidence that the charge carriers in metals are electrons.

Electrons are deflected toward the bottom surface once the current starts flowing, but the process can’t continue indefinitely. As excess charge accumulates on the top and bottom surfaces, it acts like the charge on the plates of a capacitor, creating a potential difference ΔV between the two surfaces and an electric field E=ΔV/w inside the conductor of width w. This electric field increases until the upward electric force F⃗E on the charge carriers exactly balances the downward magnetic force F⃗B. Once the forces are balanced, a steady state is reached in which the charge carriers move in the direction of the current and no additional charge is deflected to the surface.

The steady-state condition, in which FB=FE, is

FB=evdB=FE=eE=eΔVw (29.22)

Thus the steady-state potential difference between the two surfaces of the conductor, which is called the Hall voltage ΔVH, is

ΔVH=wvdB (29.23)

You learned in Chapter 27 that the drift speed is related to the current density J by J=nevd, where n is the charge-carrier density (charge carriers per m3). Thus

vd=Jne=I/Ane=Iwtne (29.24)

where A=wt is the cross-section area of the conductor. If we use this expression for vd in Equation 29.23, we find that the Hall voltage is

ΔVH=IBtne (29.25)

The Hall voltage is very small for metals in laboratory-sized magnetic fields, typically in the microvolt range. Even so, measurements of the Hall voltage in a known magnetic field are used to determine the charge-carrier density n. Interestingly, the Hall voltage is larger for poor conductors that have smaller charge-carrier densities. A laboratory probe for measuring magnetic field strengths, called a Hall probe, measures ΔVH for a poor conductor whose charge-carrier density is known. The magnetic field is then determined from Equation 29.25.

EXAMPLE 29.12 Measuring the magnetic field

A Hall probe consists of a strip of the metal bismuth that is 0.15 mm thick and 5.0 mm wide. Bismuth is a poor conductor with charge-carrier density 1.35×1025 m−3. The Hall voltage on the probe is 2.5 mV when the current through it is 1.5 A. What is the strength of the magnetic field, and what is the electric field strength inside the bismuth?

VISUALIZE The bismuth strip looks like Figure 29.41a. The thickness is t=1.5×10−4 m and the width is w=5.0×10−3 m.

SOLVE Equation 29.25 gives the Hall voltage. We can rearrange the equation to find that the magnetic field is

B=tneIΔVH=(1.5×10−4 m)(1.35×1025 m−3)(1.60× 10−19 C)1.5 A0.0025 V=0.54 T

The electric field created inside the bismuth by the excess charge on the surface is

E=ΔVHw=0.0025 V5.0×10−3 m=0.50 V/m

REVIEW 0.54 T is a fairly typical strength for a laboratory magnet.