25.2 The Potential Energy of Point Charges

FIGURE 25.7a shows two charges q1 and q2, which we will assume to be like charges. These two charges interact, and the energy of their interaction can be found by calculating the work done by the electric field of q1 on q2 as q2 moves from position xi to position xf. We’ll assume that q1 has been glued down and is unable to move, as shown in FIGURE 25.7b.

FIGURE 25.7 The interaction between two point charges.

The figure consists of two parts labeled ("a") and (b) that illustrate the interaction between two point charges.
FIGURE 25.7 Full Alternative Text

The force on q2 is entirely in the direction of motion, so cos θ=1. Thus the work done by the electric field as q2 moves from xi to xf is

Welec=∫xixf F1 on 2 dx=∫xixfKq1q2x2 dx=Kq1q2 −1x |xixf=−Kq1q2xf+Kq1q2xi (25.11)

The potential energy of the two charges is related to the work done by

ΔUelec=Uf−Ui=−Welec(i→f)=Kq1q2xf−Kq1q2xi (25.12)

By comparing the left and right sides of the equation we see that the potential energy of the two-point-charge system is

Uelec=Kq1q2x (25.13)

We chose to integrate along the x-axis for convenience, but all that matters is the distance between the charges. Thus a general expression for the electric potential energy is

Uelec=Kq1q2r=14πϵ0q1q2r  (two point charges) (25.14)

This is explicitly the energy of the system, not the energy of just q1 or q2.

NOTE   The electric potential energy of two point charges looks almost the same as the force between the charges. One important difference is the r in the denominator of the potential energy compared to the r2 in Coulomb’s law. Another is that Equation 25.14 does not have the absolute values of the charges, which means that Uelec can be negative.

Three important points need to be noted: