23.2.2 Limiting Cases

There are two cases for which we know what the result should be. First, let x become really small. As the point in Figure 23.2 approaches the origin, the fields E⃗1 and E⃗3 become opposite to each other and cancel. Thus as x→0, the field should be that of the single point charge q at the origin, a field we already know. Is it? Notice that

limx→02x(x2+d2)3/2=0 (23.3)

Thus Enet→q/4πϵ0 x2 as x→0, the expected field of a single point charge.

Now consider the opposite situation, where x becomes extremely large. From very far away, the three source charges will seem to merge into a single charge of size 3q, just as three very distant lightbulbs appear to be a single light. Thus the field for x≫d should be that of a point charge 3q. Is it?

The field is zero in the limit x→∞. That doesn’t tell us much, so we don’t want to go that far away. We simply want x to be very large in comparison to the spacing d between the source charges. If x≫d, then the denominator of the second term of E⃗net is well approximated by (x2+d2)3/2≈(x2)3/2=x3. Thus

limx≫d[1x2+2x(x2+d2)3/2]=1x2+2xx3=3x2 (23.4)

Consequently, the net electric field far from the source charges is

E⃗net(x≫d)=14πϵ0(3q)x2 î (23.5)

As expected, this is the field of a point charge 3q. These checks of limiting cases provide confidence in the result of the calculation.

FIGURE 23.3 is a graph of the field strength Enet  for the three charges of Example 23.1. Although we don’t have any numerical values, we can specify x as a multiple of the charge separation d. Notice how the graph matches the field of a single point charge when x≪d and matches the field of a point charge 3q when x≫d.

FIGURE 23.3 The electric field strength along a line perpendicular to three equal point charges.

The figure illustrates a graph of electric field strength for 3 charges.
FIGURE 23.3 Full Alternative Text