20.5.4 Diatomic Molecules

Diatomic molecules are a bigger challenge. How many degrees of freedom does a diatomic molecule have? FIGURE 20.10 shows a diatomic molecule, such as molecular nitrogen N2, oriented along the x-axis. Three degrees of freedom are associated with the molecule’s translational kinetic energy. The molecule can have a dumbbell-like end-over-end rotation about either the y-axis or the z-axis. It can also rotate about its own axis. These are three rotational degrees of freedom. The two atoms can also vibrate back and forth, stretching and compressing the molecular bond. This vibrational motion has both kinetic and potential energy—thus two more degrees of freedom.

FIGURE 20.10 A diatomic molecule can rotate or vibrate.

The figure illustrates the rotation of a diatomic molecule about the z-axis in a three-dimensional space.
FIGURE 20.10 Full Alternative Text
The figure illustrates the rotation of a diatomic molecule about the y-axis in a three-dimensional space.
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The figure illustrates the rotation of a diatomic molecule about the x-axis in a three-dimensional space.
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The figure illustrates the vibration of a diatomic molecule oriented along the x-axis in a three-dimensional space.
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Altogether, then, a diatomic molecule has eight degrees of freedom, and we would expect the thermal energy of a gas of diatomic molecules to be Eth=4NkBT. The analysis we followed for a monatomic gas would then lead to the prediction CV=4R=33.2 J/mol K. As compelling as this reasoning seems to be, this is not the experimental value of CV that was reported for diatomic gases in Table 19.4. Instead, we found CV=20.8 J/mol K.

Why should a theory that works so well for monatomic gases and solids fail so miserably for diatomic molecules? To see what’s going on, notice that 20.8 J/mol K=52R. A monatomic gas, with three degrees of freedom, has CV=32R. A solid, with six degrees of freedom, has C=3R. A diatomic gas would have CV=52R if it had five degrees of freedom, not eight.

This discrepancy was a major conundrum as statistical physics developed in the late 19th century. Although it was not recognized as such at the time, we are here seeing our first evidence for the breakdown of classical Newtonian physics. Classically, a diatomic molecule has eight degrees of freedom. The equipartition theorem doesn’t distinguish between them; all eight should have the same energy. But atoms and molecules are not classical particles. It took the development of quantum theory in the 1920s to accurately characterize the behavior of atoms and molecules. We don’t yet have the tools needed to see why, but quantum effects prevent three of the modes—the two vibrational modes and the rotation of the molecule about its own axis—from being active at room temperature.

FIGURE 20.11 shows CV as a function of temperature for hydrogen gas. CV is right at 52R for temperatures from ≈200 K up to ≈800 K. But at very low temperatures CV drops to the monatomic-gas value 32R. The two rotational modes become “frozen out” and the nonrotating molecule has only translational kinetic energy. Quantum physics can explain this, but not Newtonian physics. You can also see that the two vibrational modes do become active at very high temperatures, where CV rises to 72R. Thus the real answer to What’s wrong? is that Newtonian physics is not the right physics for describing atoms and molecules. We are somewhat fortunate that Newtonian physics is adequate to understand monatomic gases and solids, at least at room temperature.

FIGURE 20.11 Hydrogen molar specific heat at constant volume as a function of temperature.

The figure illustrates a Specific heat-versus-temperature graph .
FIGURE 20.11 Full Alternative Text

Accepting the quantum result that a diatomic gas has only five degrees of freedom at commonly used temperatures (the translational degrees of freedom and the two end-over-end rotations), we find

Eth=52NkBT=52nRTCV=52R=20.8 J/mol K(diatomic gases) (20.37)

A diatomic gas has more thermal energy than a monatomic gas at the same temperature because the molecules have rotational as well as translational kinetic energy.

While the micro/macro connection firmly establishes the atomic structure of matter, it also heralds the need for a new theory of matter at the atomic level. That is a task we will take up in Part VIII. For now, TABLE 20.1 summarizes what we have learned from kinetic theory about thermal energy and molar specific heats.

TABLE 20.1 Kinetic theory predictions for the thermal energy and the molar specific heat

System Degrees of freedom Eth CV
Monatomic gas 3 32NkBT=32nRT 32R=12.5 J/mol K
Diatomic gas 5 52NkBT=52nRT 52R=20.8 J/mol K
Elemental solid 6 3NkBT=3nRT 3R=25.0 J/mol K

EXAMPLE 20.5 The rotational frequency of a molecule

The nitrogen molecule N2 has a bond length of 0.12 nm. Estimate the rotational frequency of N2 at 20°C.

MODEL The molecule can be modeled as a rigid dumbbell of length L=0.12 nm rotating about its center.

SOLVE The rotational kinetic energy of the molecule is ϵrot=12Iω2, where I is the moment of inertia about the center. Because we have two point masses each moving in a circle of radius r=L/2, the moment of inertia is

I=mr2+mr2=2m(L2)2=mL22

Thus the rotational kinetic energy is

ϵrot=12mL22ω2=mL2ω24=π2mL2f2

where we used ω=2πf to relate the rotational frequency f to the angular frequency ω. From the equipartition theorem, the energy associated with this mode is 12NkBT, so the average rotational kinetic energy per molecule is

(ϵrot)avg=12kBT

Equating these two expressions for ϵrot gives us

π2mL2f2=12kBT

Thus the rotational frequency is

f=kBT2π2mL2=7.8×1011 rev/s

We evaluated f at T=293 K, using m=14 u=2.34×10−26 kg for each atom.

REVIEW This is a very high frequency, but these values are typical of molecular rotations.