16.7.1 Phase and Phase Difference

《 SECTION 15.2 introduced the concept of phase for an oscillator in simple harmonic motion. Phase is also important for waves. The phase of a sinusoidal wave, denoted ϕ, is the quantity (kx−ωt+ϕ0). Phase will be an important concept in Chapter 17, where we will explore the consequences of adding various waves together. For now, we can note that the wave fronts seen in Figures 16.25 and 16.26 are “surfaces of constant phase.” To see this, write the displacement as simply D(x, t)=A sin ϕ. Because each point on a wave front has the same displacement, the phase must be the same at every point.

It will be useful to know the phase difference Δϕ between two different points on a sinusoidal wave. FIGURE 16.27 shows two points on a sinusoidal wave at time t. The phase difference between these points is

Δϕ=ϕ2−ϕ1=(kx2−ωt+ϕ0)−(kx1−ωt+ϕ0)=k(x2−x1)=kΔx=2πΔxλ (16.56)

That is, the phase difference between two points on a wave depends on only the ratio of their separation Δx to the wavelength λ. For example, two points on a wave separated by Δx=12λ have a phase difference Δϕ=π rad.

FIGURE 16.27 The phase difference between two points on a wave.

The figure illustrates the phase difference between two points on a wave.
FIGURE 16.27 Full Alternative Text

An important consequence of Equation 16.56 is that the phase difference between two adjacent wave fronts is Δϕ=2π rad. This follows from the fact that two adjacent wave fronts are separated by Δx=λ. This is an important idea. Moving from one crest of the wave to the next corresponds to changing the distance by λ and changing the phase by 2π rad.

EXAMPLE 16.8 The phase difference between two points on a sound wave

A 100 Hz sound wave travels with a wave speed of 343 m/s.

  1. What is the phase difference between two points 60.0 cm apart along the direction the wave is traveling?

  2. How far apart are two points whose phase differs by 90°?

MODEL Treat the wave as a plane wave traveling in the positive x-direction.

SOLVE

  1. The phase difference between two points is

    Δϕ=2πΔxλ

    In this case, Δx=60.0 cm=0.600 m. The wavelength is

    λ=vf=343 m/s100 Hz=3.43 m

    and thus

    Δϕ=2π0.600 m3.43 m=0.350π rad=63.0°
  2. A phase difference Δϕ=90° is π/2 rad. This will be the phase difference between two points when Δx/λ=14, or when Δx=λ/4. Here, with λ=3.43 m, Δx=85.8 cm.

REVIEW The phase difference increases as Δx increases, so we expect the answer to part b to be larger than 60 cm.