4.4.2 Angular Velocity

FIGURE 4.23 shows a particle moving in a circle from an initial angular position θi at time ti to a final angular position θf at a later time tf . The change Δθ=θf−θi is called the angular displacement. We can measure the particle’s circular motion in terms of the rate of change of θ, just as we measured the particle’s linear motion in terms of the rate of change of its position s.

FIGURE 4.23 A particle moves with angular velocity ω.

The figure illustrates two positions of a particle in circular motion graphed on the x y coordinate plane.
FIGURE 4.23 Full Alternative Text

In analogy with linear motion, let’s define the average angular velocity to be

average angular velocity≡ΔθΔt (4.24)

As the time interval Δt becomes very small, Δt→0, we arrive at the definition of the instantaneous angular velocity:

ω≡limΔt→0 ΔθΔt=dθdt  (angular velocity) (4.25)

The symbol ω is a lowercase Greek omega, not an ordinary w. The SI unit of angular velocity is rad/s, but °/s, rev/s, and rev/min are also common units. Revolutions per minute is abbreviated rpm.

Angular velocity is the rate at which a particle’s angular position is changing as it moves around a circle. A particle that starts from θ=0 rad with an angular velocity of 0.5 rad/s will be at angle θ=0.5 rad after 1 s, at θ=1.0 rad after 2 s, at θ=1.5 rad after 3 s, and so on. Its angular position is increasing at the rate of 0.5 radian per second. A particle moves with uniform circular motion if and only if its angular velocity ω is constant and unchanging.

Angular velocity, like the velocity vs of one-dimensional motion, can be positive or negative. The signs shown in FIGURE 4.24 are based on the fact that θ was defined to be positive for a counterclockwise rotation. Because the definition ω=dθ/dt for circular motion parallels the definition vs=ds/dt for linear motion, the graphical relationships we found between vs and s in Chapter 2 apply equally well to ω and θ:

ω=slope of the  θ-versus-t graph at time tθf=θi+area under​​ the ω-versus-t curve between​ ti and tf=θi+ω Δt (4.26)

FIGURE 4.24 Positive and negative angular velocities.

The figure illustrates positive and negative angular velocities using a rotating cylinder. The vertically oriented circular face of the cylinder is shown.
FIGURE 4.24 Full Alternative Text

You will see many more instances where circular motion is analogous to linear motion with angular variables replacing linear variables. Thus much of what you learned about linear kinematics carries over to circular motion.

EXAMPLE 4.10 A graphical representation of circular motion

FIGURE 4.25 shows the angular position of a painted dot on the edge of a rotating wheel. Describe the wheel’s motion and draw an ω-versus-t graph.

FIGURE 4.25 Angular position graph for the wheel of Example 4.10.

The figure illustrates an angular position-versus-time graph for a wheel.

SOLVE Although circular motion seems to “start over” every revolution (every 2π rad), the angular position θ continues to increase. θ=6π rad corresponds to three revolutions. This wheel makes 3 ccw rev (because θ is getting more positive) in 3 s, immediately reverses direction and makes 1 cw rev in 2 s, then stops at t=5 s and holds the position θ=4π rad. The angular velocity is found by measuring the slope of the graph:

t=0−3 s slope=Δθ/Δt=6π rad/3 s=2π rad/st=3−5 s slope=Δθ/Δt=−2π rad/2 s=−π rad/st>5 s slope=Δθ/Δt=0 rad/s

These results are shown as an ω-versus-t graph in FIGURE 4.26. For the first 3 s, the motion is uniform circular motion with ω = 2π rad/s. The wheel then changes to a different uniform circular motion with ω=−π rad/s for 2 s, then stops.

FIGURE 4.26 ω-versus-t graph for the wheel of Example 4.10.

The figure illustrates an angular velocity-versus-time graph for a wheel.

NOTE   In physics, we nearly always want to give results as numerical values. Example 4.9 had a π in the equation, but we used its numerical value to compute v=5.0 m/s. However, angles in radians are an exception to this rule. It’s okay to leave a π in the value of θ or ω, and we have done so in Example 4.10.

Not surprisingly, the angular velocity ω is closely related to the period and speed of the motion. As a particle goes around a circle one time, its angular displacement is Δθ=2π rad during the interval Δt=T. Thus, using the definition of angular velocity, we find

|ω|=2π radT  or  T=2π rad|ω| (4.27)

The period alone gives only the absolute value of |ω|, which is the angular speed. You need to know the direction of motion to determine the sign of ω.

EXAMPLE 4.11 At the roulette wheel

A small steel roulette ball rolls ccw around the inside of a 30-cm-diameter roulette wheel. The ball completes 2.0 rev in 1.20 s.

  1. What is the ball’s angular velocity?

  2. What is the ball’s position at t=2.0 s? Assume θi=0.

MODEL Model the ball as a particle in uniform circular motion.

SOLVE a. The period of the ball’s motion, the time for 1 rev, is T=0.60 s. Angular velocity is positive for ccw motion, so

ω=2π radT=2π rad0.60 s=10.47 rad/s

b. The ball starts at θi=0 rad. After Δt=2.0 s, its position is

θf=0 rad+(10.47 rad/s)(2.0 s)=20.94 rad

where we’ve kept an extra significant figure to avoid round-off error. Although this is a mathematically acceptable answer, an observer would say that the ball is always located somewhere between 0° and 360°. Thus it is common practice to subtract an integer number of 2π rad, representing the completed revolutions. Because 20.94/2π=3.333, we can write

θf=20.94 rad=3.333×2π rad=3×2π rad+0.333×2π rad=3×2π rad+2.09 rad

In other words, at t=2.0 s the ball has completed 3 rev and is 2.09 rad=120° into its fourth revolution. An observer would say that the ball’s position is θf=120°.

As Figure 4.21 showed, the velocity vector v ⃗ is always tangent to the circle. In other words, the velocity vector has only a tangential component, which we will designate vt. The tangential velocity is positive for ccw motion, negative for cw motion.

Combining v=2πr/T for the speed with ω=2π/T for the angular velocity—but keeping the sign of ω to indicate the direction of motion—we see that the tangential velocity and the angular velocity are related by

vt=ωr  (with ω in rad/s) (4.28)

Because vt is the only nonzero component of v ⃗, the particle’s speed is v=|vt|=|ω|r. We’ll sometimes write this as v=ωr if there’s no ambiguity about the sign of ω.

NOTE   While it may be convenient in some problems to measure ω in rev/s or rpm, you must convert to SI units of rad/s before using Equation 4.28.

As a simple example, a particle moving cw at 2.0 m/s in a circle of radius 40 cm has angular velocity

ω=vtr=−2.0 m/s0.40 m=−5.0 rad/s

where vt and ω are negative because the motion is clockwise. Notice the units. Velocity divided by distance has units of s−1. But because the division, in this case, gives us an angular quantity, we’ve inserted the dimensionless unit rad to give ω the appropriate units of rad/s.