4.3 Relative Motion

FIGURE 4.17 shows Amy and Bill watching Carlos on his bicycle. According to Amy, Carlos’s velocity is vx=5 m/s. Bill sees the bicycle receding in his rearview mirror, in the negative x-direction, getting 10 m farther away from him every second. According to Bill, Carlos’s velocity is vx=−10 m/s. Which is Carlos’s true velocity?

FIGURE 4.17 Velocities in Amy’s reference frame.

A pictorial representation of the relative velocities of a bicycle and a car with respect to a woman named Amy.
FIGURE 4.17 Full Alternative Text

Velocity is not a concept that can be true or false. Carlos’s velocity relative to Amy is (vx)CA=5 m/s, where the subscript notation means “C relative to A.” Similarly, Carlos’s velocity relative to Bill is (vx)CB=−10 m/s. These are both valid descriptions of Carlos’s motion.

It’s not hard to see how to combine the velocities for one-dimensional motion:

(4.16)

An equation depicting the addition of two relative velocities.

We’ll justify this relationship later in this section and then extend it to two-dimensional motion.

Equation 4.16 tells us that the velocity of C relative to B is the velocity of C relative to A plus the velocity of A relative to B. Note that

(vx)AB=−(vx)BA (4.17)

because if B is moving to the right relative to A, then A is moving to the left relative to B. In Figure 4.17, Bill is moving to the right relative to Amy with (vx)BA=15 m/s, so (vx)AB=−15 m/s. Knowing that Carlos’s velocity relative to Amy is 5 m/s, we find that Carlos’s velocity relative to Bill is, as expected, (vx)CB=(vx)CA+(vx)AB=5 m/s+(−15) m/s=−10 m/s.

EXAMPLE 4.6 A speeding bullet

The police are chasing a bank robber. While driving at 50 m/s, they fire a bullet to shoot out a tire of his car. The police gun shoots bullets at 300 m/s. What is the bullet’s speed as measured by a TV camera crew parked beside the road?

MODEL Assume that all motion is in the positive x-direction. The bullet is the object that is observed from both the police car and the ground.

SOLVE The bullet B’s velocity relative to the gun G is (vx)BG=300 m/s. The gun, inside the car, is traveling relative to the TV crew C at (vx)GC=50 m/s. We can combine these values to find that the bullet’s velocity relative to the TV crew on the ground is

(vx)BC=(vx)BG+(vx)GC=300 m/s+50 m/s=350 m/s

REVIEW It should be no surprise in this simple situation that we simply add the velocities.