APPENDIX A
Mathematics Review

Algebra

Using exponents: a−x=1ax axay=a(x + y) axay=a(x− y) (ax)y=ax y
         
a0=1 a1=a a1/n=an
         
Fractions: (ab)(cd)=acbd a/bc/d=adbc 11/a=a
         
Logarithms: If a=ex, then ln(a)=x ln(ex)=x eln (x)=x
         
ln(ab)=ln(a)+ln(b) ln(ab)=ln(a)−ln(b) ln(an)=nln(a)
The expression ln(a+b) cannot be simplified.
Quadratic equation: The quadratic equation ax2+bx+c=0 has the two solutions x=−b±b2−4ac2a.
Linear equations:

The graph of the equation y=ax+b is a straight line. a is the slope of the graph. b is the y-intercept.

The figure illustrates a graph of the equation y equals "a" x plus b.
Proportionality: To say that y is proportional to x, written y∝x, means that y=ax, where a is a constant. Proportionality is a special case of linearity. A graph of a proportional relationship is a straight line that passes through the origin. If y∝x, then
y1y2=x1x2
Distance:

The distance between points with coordinates (x1,y1) and (x2,y2) is

d=(x2−x1)2+(y2−y1)2

Geometry and Trigonometry

Area and volume: Rectangle
A = ab
The figure illustrates a rectangle with width labeled "a" and length labeled b.
Rectangular box
V = abc
The figure illustrates a rectangular box with width labeled "a", length labeled b, and height labeled c.
Triangle
A = 12ab
The figure illustrates a triangle with base labeled "a" and height labeled b.
Right circular cylinder
V = πr2l
The figure illustrates a cylinder with radius labeled r from the center of the end face and length labeled l.
Circle
C = 2πr
A = πr2
The figure illustrates a circle with radius labeled r from the center of the circle.
Sphere
A = 4πr2
V = 43πr3
The figure illustrates a sphere with radius labeled r from the center of the sphere.
Arc length and angle:

The angle θ in radians is defined as θ=s/r.

The arc length that spans angle θ is s=rθ.

2π rad=360°

The figure illustrates a sector with arc length labeled s, radius labeled r on both the sides , and central angle labeled theta radians.
Right triangle:

Pythagorean theorem c=a2+b2 or a2+b2=c2

sin θ=bc=far sidehypotenuseθ= sin −1(bc)cos θ=ac=adjacent sidehypotenuseθ= cos −1(ac)tan θ=ba=far sideadjacent sideθ= tan −1(ba)

The figure illustrates a right angle triangle with the adjacent side labeled "a", far side labeled b, and hypotenuse labeled c. The angle made by the adjacent and hypotenuse side is labeled theta.
General triangle:

α+β+γ=180°=π rad

Law of cosines c2=a2+b2−2ab cos γ

The figure illustrates a triangle with base labeled "a", the right side labeled b, and the left side labeled c. The vertex angle at the top is labeled alpha, lower left is labeled beta, and lower right is labeled gamma.
Identities: tan α=sin αcos α sin2 α+ cos2 α=1
sin(−α)=−sin α cos(−α)=cos α
sin(α±β)=sin α  cos β±cos α  sin β cos(α±β)=cos α  cos β∓sin α  sin β
sin(2α)=2 sin α  cos α cos(2α)=cos2 α−sin2 α
sin(α±π/2)=±cos α cos(α±π/2)=∓sin α
sin(α±π)=−sin α cos(α±π)=−cos α
Trigonometric

functions:

sinθ and cosθ are the functions of the angle θ with period 2π rad.
The figure consists of two parts that illustrate a sine and cos wave function graphically.

Expansions and Approximations

Binomial expansion: (1+x)n=1+nx+n(n−1)2 x2+⋯
Binomial approximation: (1+x)n≈1+nx if x≪1
Trigonometric expansions: sin α=α−α33!+α55!−α77!+⋯ for α in rad
cos α=1−α22!+α44!−α66!+⋯ for α in rad
Small-angle approximation: If α≪1 rad, then sin α≈ tan α≈α and cos α≈1.
The small-angle approximation is excellent for α<5° (≈ 0.1 rad) and generally acceptable up to α≈10°.

Calculus

The letters a and n represent constants in the following derivatives and integrals.

Derivatives

ddx(a)=0 ddx(ln(ax)​) ​​​=1x
 
ddx(ax)=a ddx(eax)=aeax
 
ddx(ax)=−ax2 ddx(sin(ax)) ​​​=a cos(ax)
 
ddx(axn)=anxn−1 ddx(cos(ax)​​​​) ​​=−a sin(ax)

Integrals

∫x dx=12x2 ∫dx(x2±a2)3/2=±xa2x2±a2
 
∫x2 dx=13x3 ∫x dx(x2±a2)3/2=−1x2±a2
 
∫1x2dx=−1x ∫eax dx=1a eax
 
∫xn dx=xn +1n+1  n≠−1 ∫xe−x dx=−(x+1)e−x
 
∫dxx=ln x ∫x2e−x dx=−(x2+2x+2)e−x
 
∫dxa+x=ln(a+x) ∫sin(ax) dx=−1a cos(ax)
 
∫x dxa+x=x−a ln(a+x) ∫cos(ax) dx=1a sin(ax)
 
∫dxx2±a2=ln (x+x2±a2) ∫sin2(ax) dx=x2−sin(2ax)4a
 
∫x dxx2±a2=x2±a2 ∫cos2(ax) dx=x2+sin(2ax)4a
 
∫dxx2+a2=1a tan−1(xa) ∫0∞xne−ax dx=n!an+1
 
∫dx(x2+a2)2=12a3 tan−1(xa)+x2a2(x2+a2) ∫0∞e−ax2 dx=12πa