Chapter 21: Answers to Stop to Think Questions and Odd-Numbered Exercises and Problems

Stop to Think Questions

  1. 1. WD>WA=WB>WC. Wout=QH−QC.

  2. 2. b. Energy conservation requires QH=QC+Win. The refrigerator will exhaust more heat out the back than it removes from the front. A refrigerator with an open door will heat the room rather than cool it.

  3. 3. c. Wout= area inside triangle=1000 J. η=Wout/QH=(1000 J)/(4000 J)=0.25.

  4. 4. To conserve energy, the heat QH exhausted to the hot reservoir needs to be QH=QC+Win=40 J+10 J=50 J, not 30 J.

  5. 5. b. The efficiency of this engine would be η=Wout/QH=0.6. That exceeds the Carnot efficiency ηCarnot=1−TC/TH=0.5, so it is not possible.

Exercises and Problems

  1. 1. 0.33

  2. 3. 6.4 kg/s

  3. 5.

    1. 200 J

    2. 250 J

  4. 7.

    1. 13 kJ/cycle

    2. 50 kJ

  5. 9.

    ΔEth Ws Q
    A − + 0
    B + 0 +
    C 0 − −
  6. 11. 800 cm3

  7. 13.

    1. 30 J, 145 J

    2. 21%

  8. 15. 285 J

  9. 17. 0.24

  10. 19.

    1. 5.0 kW

    2. 1.7

  11. 21.

    1. 64 J

    2. 1.6

  12. 23.

    1. Engine c violates the first law.

    2. Engine b violates the second law.

  13. 25.

    1. 40%

    2. 215°C

  14. 27. 135°C

  15. 29. 5.0 kJ

  16. 31.

    1. 6.3

    2. 32 W

    3. 0.23 kW

  17. 33.

    1. 0 J/K

    2. −1.3 J/K

    3. 1.3 J/K

  18. 37.

  19. 39. 83 W

  20. 41.

    1. 3.6×106 J

    2. 3.0×105 J

  21. 43. 8.3%

  22. 45. 6.4 J

  23. 47.

    1. 2.5 kW

    2. $45

  24. 49. 57 g

  25. 51.

    1. 48 m

    2. 32%

  26. 53. 37%

  27. 55.

    1. ΔEth (J) Ws(J) Q (J)
      1→2    13.93      3.04    16.97
      2→3 −10.13             0 −10.13
      3→1    −3.80 −1.52    −5.32
      Net               0      1.52        1.52
    2. 9.0%

    3. 13 W

  28. 57.

    1. 1.10 kW

    2. 9.01%

  29. 59.

    1. 1000 cm3, 696 kPc, 522 K

    2. ΔEth (J) Ws(J) Q (J)
      1→2 741.1 0 741.1
      2→3 −741.1 741.1 0
      3→1 0 −554.5 −554.5
      Net 0 186.6 186.6
    3. 25%

  30. 61.

    1. 4→3, 3→2

    2. QH

    3. QH=22.28×105 J, QC=26.33×105 J

    4. Win=4.05×105 J

    5. No

  31. 63.

    1. T1=1.6 kK, T2=2.4 kK, T3=6.5 kK

    2. ΔEth (J) Ws (J) Q (J)
      1→2 327 −327 0
      2→3 1692 677 2369
      3→1 −2019 0 −2019
      Net 0 350 350

  32. 65.

    1. 1.1×103°C

  33. 67.

    1. QC=80 J

  34. 69. 5.3×104 J

  35. 71.

    1. 1.19

    2. 227 W

  36. 73.